35x^2-2x-48=0

Solution for 35x^2-2x-48=0 equation:

35x^2-2x-48=0

a = 35; b = -2; c = -48;
Δ = b2-4ac
Δ = -22-4·35·(-48)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-82}{2*35}=\frac{-80}{70}
=-1+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+82}{2*35}=\frac{84}{70}
=1+1/5
$